GRE全真题90(04)之二
SHALLOW:
arbitrary
painstaking
profound
restive
contrite
答案：(C)
浅的，肤浅的adj.
A.武断的，任性多变的
B. 费力的，劳苦的
C. 深刻的，深沉的
D. 不安的，浮澡的
E. 忏悔的，悔恨的
IMMUNE:
toxic
virulent
convalescent
having little energy
having no resistance
答案：(E)
有免疫力的，免除的adj.
A.有毒的
B. 病毒的
C. 病后康复的
D. 有气无力的
E. 没有抵抗力的
PROPAGATE:
hesitate to join
hope to prosper
decide to accept
begin to falter
fail to multiply
答案：(E)
繁殖，宣传v.
A.不愿参加
B. 希望繁荣
C. 决定接受
D. 开始动摇
E. 没能繁殖
LULL:
pronounced interest
intense discussion
speedy resolution
increased activity
enhanced performance
答案：(D)
活动稍歇期，平静n.
A.强烈的兴趣
B. 激烈的讨论
C. 迅速的决策
D. 增强的活动
E. 改进的表演
PERPETUAL:
antecedent
coincident
intermittent
precipitous
languorous
答案：(C)
不断的，永恒的adj.
A.先时的(前事，先行词n.)
B. 巧合的
C. 间歇的，间断的
D. 仓促的，陡峭的
E. 懒散的，倦怠的
ACCOLADE:
guarded emotion
scarce resource
temporization
repercussion
criticism
答案：(E)
极力赞扬，授予武士爵位n.
A.谨慎的感情
B. 稀少的资源
C. 拖延时间，调停
D. 反响，影响，回声
E. 批评，评论
GAMBOL:
admit
plod
ruin
follow
fret
答案：(B)
欢呼雀跃v.
A.承认，容许
B. 沉重走路，跋涉
C. 毁坏(废墟n.)
D. 跟随
E. 烦恼(磨损v.)
REFUTATION:
approval
verification
amplification
concurrence
computation
答案：(B)
反驳，驳斥n.
A.批准，赞同
B. 证实，确证
C. 放大，扩大
D. 同时发生的事，一致
E. 计算
REQUITE:
incite
applaud
consume quickly
make inhospitable
leave unrepaid
答案：(E)
报答，付款v.
A.鼓励，激励
B. 鼓掌，赞扬
C. 快速消耗
D. 使不友好
E. 不加回报，不付款
REVERE:
imitate
dismiss
confuse
profane
disgrace
答案：(D)
尊敬v.
A.模仿
B. 解散，不考虑
C. 混淆
D. 亵渎，玷污(不洁的adj.)
E. 丢脸，使…耻辱
MOLLIFY:
ire
commence
abate
oppose
infuse
答案：(A)
抚慰，减轻v.
A.激怒(怒气n.)
B. 开始
C. 降低，减少
D. 反对，对立
E. 灌输，浸泡
A group of eight people is going camping in tents- tent 1, tent 2, and tent
3. The group consists of two women-V and X-and six girls-K, L, M, O, P,
and T. Tent assignments will be made as follows:
There will be no more than three persons in a tent.
V will be in tent 1.
V will not be in a tent with her daughter O, and X will not be in tent
with her daughter P.
K, L, and M, who are close friends, will be in a tent together.
Which of the following can be in tent 1 ?
K
L
M
O
X
答案：(E)
读题： 8个人分成3组, 包括 2 women (V X), 6 girl (K L M O P T)
写条件：
1、每组最多3人
2、V=1 (表示V在1)
3、V≠O, X≠P (表示V和O不在同一组, X和P不在同一组)
4、(KLM) (表示KLM在同一组)
条件总结：
*由条件1得出: 一共8人分3组，每组最多3人，则3组是（3，3，2）分配
*由条件4得出，(KLM)在3人组，
到此为止，整个题目已迎刃而解，分组题的关键是每组的数目分配和谁和谁不在同一组的条件。比如本题的X≠P，当有3组的情况下，假若固定了其中的一组，这样的条件就可以用上。例如题目5
If K is in tent 2, which of the following must be true?
M is intent 3.
O is intent 3.
P is in tent 2.
T is in tent 1.
X is intent 3.
答案：(B)
读题： 8个人分成3组, 包括 2 women (V X), 6 girl (K L M O P T)
写条件：
1、每组最多3人
2、V=1 (表示V在1)
3、V≠O, X≠P (表示V和O不在同一组, X和P不在同一组)
4、(KLM) (表示KLM在同一组)
条件总结：*由条件1得出: 一共8人分3组，每组最多3人，则3组是（3，3，2）分配*由条件4得出，(KLM)在3人组，到此为止，整个题目已迎刃而解，分组题的关键是每组的数目分配和谁和谁不在同一组的条件。比如本题的X≠P，当有3组的情况下，假若固定了其中的一组，这样的条件就可以用上。例如题目5
If the two women are together in a tent,which of the following is a pair of
girls who must be together in a tent?
K and P
L and T
M and O
O and P
P and T
答案：(D)
读题： 8个人分成3组, 包括 2 women (V X), 6 girl (K L M O P T)
写条件：
1、每组最多3人
2、V=1 (表示V在1)
3、V≠O, X≠P (表示V和O不在同一组, X和P不在同一组)
4、(KLM) (表示KLM在同一组)
条件总结：*由条件1得出: 一共8人分3组，每组最多3人，则3组是（3，3，2）分配*由条件4得出，(KLM)在3人组，到此为止，整个题目已迎刃而解，分组题的关键是每组的数目分配和谁和谁不在同一组的条件。比如本题的X≠P，当有3组的情况下，假若固定了其中的一组，这样的条件就可以用上。例如题目5
If X is in tent 2, which of the following must be in the same tent as V ?
K
L
O
P
T
答案：(D)
读题： 8个人分成3组, 包括 2 women (V X), 6 girl (K L M O P T)
写条件：
1、每组最多3人
2、V=1 (表示V在1)
3、V≠O, X≠P (表示V和O不在同一组, X和P不在同一组)
4、(KLM) (表示KLM在同一组)
条件总结：*由条件1得出: 一共8人分3组，每组最多3人，则3组是（3，3，2）分配*由条件4得出，(KLM)在3人组，到此为止，整个题目已迎刃而解，分组题的关键是每组的数目分配和谁和谁不在同一组的条件。比如本题的X≠P，当有3组的情况下，假若固定了其中的一组，这样的条件就可以用上。例如题目5
If L is in tent 3 and the two women are not in the same tent as each
other, the people in tent 2 can be
M and T only
X and T only
K, M, and O
O, P, and X
O, T, and X
答案：(E)
读题： 8个人分成3组, 包括 2 women (V X), 6 girl (K L M O P T)
写条件：
1、每组最多3人
2、V=1 (表示V在1)
3、V≠O, X≠P (表示V和O不在同一组, X和P不在同一组)
4、(KLM) (表示KLM在同一组)
条件总结：*由条件1得出: 一共8人分3组，每组最多3人，则3组是（3，3，2）分配*由条件4得出，(KLM)在3人组，到此为止，整个题目已迎刃而解，分组题的关键是每组的数目分配和谁和谁不在同一组的条件。比如本题的X≠P，当有3组的情况下，假若固定了其中的一组，这样的条件就可以用上。例如题目5
如果L=3, 两个女的不在同一组, 在第2组的人是谁?
解题步骤:(E)
1、 L=3, (KLM)在一组, ∴(KLM)在第3组, 由此第3组已经确定
2、 至此,没有别的条件可用, 转向固定条件V=1, 由V≠O得,
O=2 ; 而问题中已知两个女的(V,X)不在同一组, ∴X=2; 而X≠P,
∴P=1; T是没有任何限制的元素,可以在第1组或者第2组 ?
1：V P
2：O X
3：KLM
If V and T are together in a tent, it is possible that
K and P are together in a tent
O and T are together in a tent
O and X are the only people in tent 2
P and X are the only people in tent 3
T and V are the only people in tent 1
答案：(C)
读题： 8个人分成3组, 包括 2 women (V X), 6 girl (K L M O P T)
写条件：
1、每组最多3人
2、V=1 (表示V在1)
3、V≠O, X≠P (表示V和O不在同一组, X和P不在同一组)
4、(KLM) (表示KLM在同一组)
条件总结：*由条件1得出: 一共8人分3组，每组最多3人，则3组是（3，3，2）分配*由条件4得出，(KLM)在3人组，到此为止，整个题目已迎刃而解，分组题的关键是每组的数目分配和谁和谁不在同一组的条件。比如本题的X≠P，当有3组的情况下，假若固定了其中的一组，这样的条件就可以用上。例如题目5
Grammarians have for years condemned as ungrammatical the English
phrase "between you and I, " insisting that the correct phrasing is
"between you and me," with the objective case after a preposition.
Such condemnations, however, are obviously unfounded, because Shakespeare
himself, in The Merchant of Venice, wrote, "All debts are cleared between
you and I."
Which of the following, if true, most seriously weakens the argument above?
In his plays, Shakespeare intentionally had some of his characters use phrases
he considered ungrammatical.
The phrase "between you and I" appears infrequently in
Shakespeare's writings.
The more modern an English word or phrase, the less likely that modern grammarians
will consider it acceptable for formal usage.
Many modern speakers of English sometimes say "between you and I"
and sometimes say "between you and me."
Most native speakers of English who choose to say "between you and
I" do so because they know that Shakespeare used that phrase.
答案：(A)
Around 1850 there were about 800 farms in Otsego County. By the 1950's the
number of farms had dropped to around 400. By 1988 there were only 81 farms in
operation. Therefore, the amount of land in the county that is devoted to
farming has dropped by about 90 percent in the past 140 years.
A major flaw in the argument above is that it
counts the number of farms only approximately
fails to say whether the use now being made of the land previously devoted
to farming is income-producing
ignores the possibility that the average size of farms has changed
gives data for only 3 of the past 140 years
does not take into account the type of product or crop each farm yields
答案：(C)
Senator: Jones is highly qualified for appointment as a judge, as
evidenced by Jones's receiving a unanimous vote of "qualified" on
the formal rating scale used by the Lawyers' Committee. That committee advises
the Senate on judicial appointments.
Which of the following, if true, is the best reason for dismissing the
senator's claim that Jones is highly qualified?
Several members of the Lawyers' Committee are not themselves qualified for
judicial appointments.
The Lawyers' Committee does not advise the Senate on all judicial appointments.
The Lawyers' Committee gives a unanimous vote of "qualified" only
to those candidates for judicial appointments who meet the committee's stringent
standards for appropriate prior experience and ethical conduct.
The Lawyers' Committee gives a unanimous vote of either "highly
qualified" or "very highly qualified" to 95 percent of all
candidates for judicial appointments.
Jones, like most lawyers, is a member of the professional organization that
originally suggested the establishment of the Lawyers' Committee.
答案：(D)
问题: 下面那一个如果正确的话,最后理由驳斥参议员认为Jones非常有资格的宣称?
读题: 参议员：Johes
非常有资格被任命为法官，证据是在律师委员会所使用的正式评分准则中，全体一致投票Johes
有资格。而该委员会在法官任命上为参议院提供建议.本题论据由as
evidenced by 引导，论点为第一句话。因为unanimous vote of
"qualified", 所以，highly qualified.
分析:(答案Ｄ）
* 对于weaken来讲,
1、选项中说到和论据、论点或两者之间的联系有不一样的就可作为答案
2、有其他原因影响论点也是weaken
(尽管unanimous vote of "qualified，但还有别的因素影响是否highly
qualified)
C.
律师委员会仅仅对那些满足委员会严格要求的法官任命候选人，全体一致投票"有资格，C在加强论据，是支持。
D. 律师委员会对95%的候选人，全体一致投票或者"highly
qualified"，或者"qualified"。D中的95%恰恰说明Johes
只是许多人中的一个而已，在A-B之间进行了削弱，如果95%替换为5%，那就是support.
E. 与qualify无关，不要进一步联想（他是最初建议律师委员会创建的组织成员之一， 所以律师委员会投以unanimous，所以反对了论据，这种推理是绝对要不得的).
On a tax form, a taxpayer is filling in numbers on eleven lines-F, G, H, I,
K, L, M, Q, R, V,and Z-according to the following instructions and no others:
Line F must be derived from lines G, H, and V as G plus H minus V.
Line L must be derived from lines I and K as I plus K.
Line Q must be derived from lines L and M as L minus M.
Line R must be derived from lines Q and F as Q minus F.
Line V must be derived from line L as five percent of L.
Line Z must be derived from line R as half of R.
cannot be derived unless which of the following is known?
F
G
H
I
M
答案：(D)
读题:在一个税收报表中,一个纳税者在11行中填写数字(F,G,H,I,K,L,M,Q,R,V,Z)
写条件：
F=G+H-V
L=I+K
Q=L-M
R=Q-F
V=5%L
Z=1/2R
V不能得到，除非下面哪一个知道？
解题步骤:(D)
1、看一下V是怎么得到的呢？当然要看等式左边,V等于什么,
V=5%L, ∴V从L得到但是答案中并没有L，那么继续找L怎么得到呢？
2、L=I+K, L从I、K得到，故D对。
cannot be derived unless which of the following is known?
K
M
Q
R
Z
答案：(A)
读题:在一个税收报表中,一个纳税者在11行中填写数字(F,G,H,I,K,L,M,Q,R,V,Z)
写条件：
F=G+H-V
L=I+K
Q=L-M
R=Q-F
V=5%L
Z=1/2R
It is necessary for the taxpayer to know H before the taxpayer can derive
L
M
Q
R
V
答案：(D)
读题:在一个税收报表中,一个纳税者在11行中填写数字(F,G,H,I,K,L,M,Q,R,V,Z)
写条件：
F=G+H-V
L=I+K
Q=L-M
R=Q-F
V=5%L
Z=1/2R
在得到什么之前，需要知道H？
解题步骤:答案(D)
1、应该从等式右边找H；由F=G+H-V得,要想得到F,必须知道H,但是答案中并没有F，那么继续寻找在得到什么之前，需要知道F
2、在等式右边找F，R=Q-F，要想得到R,必须知道F, 故D对。
If the taxpayer knows I, H, K, and M but not G, which of the following is a
pair of lines that the taxpayer can derive?
F and V
L and Q
L and R
R and V
R and Z
答案：(B)
读题:在一个税收报表中,一个纳税者在11行中填写数字(F,G,H,I,K,L,M,Q,R,V,Z)
写条件：
F=G+H-V
L=I+K
Q=L-M
R=Q-F
V=5%L
Z=1/2R
At a conference, exactly seven speakers-Qualls, Ramirez, Smith, Titus,
Umana,Vines, and Wertz-are to speak.In the schedule for the conference, there
are seven time slots available for speakers, and the time slots are
numbered consecutively 1 through 7. Exactly one speaker must be assigned to
each time slot according to the following conditions:
Qualls must speak immediately before or immediately after Titus speaks.
Titus must speak sometime before Ramirez speaks.
Smith must speak in either time slot 1 or time slot 7.
Vines must speak in time slot 4.
Which of the following must be true?
Qualls speaks sometime before Ramirez speaks.
Qualls speaks sometime before Vines speaks.
Smith speaks sometime before Titus speaks.
Vines speaks sometime before Ramirez speaks.
Wertz speaks sometime before Vines speaks.
答案：(A)
读题:7个人Q,R,S,T,U,V,W在会议上作演讲,每人在一个time slot.
写条件:
1、 (QT) (表示Q和T紧密相邻,并且不分前后)
2、 T<R (表示T在R的前面)
3、 S=1/7 (表示S在1或者7)
4、 V= 4 (表示V在4)
条件总结：
* 条件1和2联合:(QT)<R
* 注意: U, W没有任何限制，为等价元素。
If Ramirez speaks immediately before Vines speaks, which of the following
could be true?
Qualls speaks in time slot 5.
Smith speaks in time slot 1.
Titus speaks in time slot 3.
Umana speaks in time slot 2.
Wertz speaks in time slot 6.
答案：(E)
读题:7个人Q,R,S,T,U,V,W在会议上作演讲,每人在一个time slot.
写条件:
1、 (QT) (表示Q和T紧密相邻,并且不分前后)
2、 T<R (表示T在R的前面)
3、 S=1/7 (表示S在1或者7)
4、 V= 4 (表示V在4)
条件总结：
* 条件1和2联合:(QT)<R
* 注意: U, W没有任何限制，为等价元素。
如果 RV(表示R immediatelly before V), 下面那一个可能正确?
解题步骤:答案(E)
1 2 3 4 5 6 7
(Q T) R V S
1、 由RV, V=4得, R=3
2、 解题方向到R，(QT)<R， ∴(QT)=1,2
3、 QT没有别的限制，元素和位置同等重要，位置1有限制，由S=1/7得S=7
4 U、W在(5,6)
If Ramirez speaks sometime before Smith speaks, which of the following must
be true?
Qualls speaks sometime before Umana speaks.
Ramirez speaks sometime before Vines speaks.
Titus speaks sometime before Vines speaks.
Umana speaks sometime before Ramirez speaks.
Wertz speaks sometime before Qualls speaks.
答案：(C)
读题:7个人Q,R,S,T,U,V,W在会议上作演讲,每人在一个time slot.
写条件:
1、 (QT) (表示Q和T紧密相邻,并且不分前后)
2、 T<R (表示T在R的前面)
3、 S=1/7 (表示S在1或者7)
4、 V= 4 (表示V在4)
条件总结：
* 条件1和2联合:(QT)<R
* 注意: U, W没有任何限制，为等价元素。
如果R<S，下面哪一个must be true ?
解题步骤:答案(C)
4 5 6 7
V S
1、与R相关的条件(QT)<R, ∴(QT)<R<S
2、与S相关的条件S=1/7, ∴S=7
3、从选项中得到,题目寻求元素的前后关系, 由步骤1和2,
以及V=4得,
QT<位置4
If Umana is to speak in time slot 2, there will be a total of how many
scheduling possibilities from which to select the schedule of speakers?
One
Two
Three
Four
Six
答案：(B)
读题:7个人Q,R,S,T,U,V,W在会议上作演讲,每人在一个time slot.
写条件:
1、 (QT) (表示Q和T紧密相邻,并且不分前后)
2、 T<R (表示T在R的前面)
3、 S=1/7 (表示S在1或者7)
4、 V= 4 (表示V在4)
条件总结：
* 条件1和2联合:(QT)<R
* 注意: U, W没有任何限制，为等价元素。
如果U=2,对于演讲者的选取共有几种选法？
解题步骤:答案(C)
1、条件中没有涉及U的条件，也没有位置2的条件,
先用固定条件。有V=4
1 2 3 4 5 6 7
S U V (Q T) R
2、目前已经没有别的条件可用,但是我们发现7个位置，V在中间4，U=2，它使得
要有连续的话只能在567，由条件(QT)<R得，R=7, 再由S=1/7得,
S=1 ,
∴一共有2种选法(QT)=56
(*连续条件的使用就必须要存在连续的位置,当题目中存在连续的条件,在解题时没有条件可用时,往往就需要用到这种固定的思维)
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